'Weak Dependency Graph [60.0]'
------------------------------
Answer:           YES(?,O(n^2))
Input Problem:    innermost runtime-complexity with respect to
  Rules:
    {  h(x, c(y, z)) -> h(c(s(y), x), z)
     , h(c(s(x), c(s(0()), y)), z) -> h(y, c(s(0()), c(x, z)))}

Details:         
  We have computed the following set of weak (innermost) dependency pairs:
   {  h^#(x, c(y, z)) -> c_0(h^#(c(s(y), x), z))
    , h^#(c(s(x), c(s(0()), y)), z) -> c_1(h^#(y, c(s(0()), c(x, z))))}
  
  The usable rules are:
   {}
  
  The estimated dependency graph contains the following edges:
   {h^#(x, c(y, z)) -> c_0(h^#(c(s(y), x), z))}
     ==> {h^#(c(s(x), c(s(0()), y)), z) ->
          c_1(h^#(y, c(s(0()), c(x, z))))}
   {h^#(x, c(y, z)) -> c_0(h^#(c(s(y), x), z))}
     ==> {h^#(x, c(y, z)) -> c_0(h^#(c(s(y), x), z))}
   {h^#(c(s(x), c(s(0()), y)), z) -> c_1(h^#(y, c(s(0()), c(x, z))))}
     ==> {h^#(c(s(x), c(s(0()), y)), z) ->
          c_1(h^#(y, c(s(0()), c(x, z))))}
   {h^#(c(s(x), c(s(0()), y)), z) -> c_1(h^#(y, c(s(0()), c(x, z))))}
     ==> {h^#(x, c(y, z)) -> c_0(h^#(c(s(y), x), z))}
  
  We consider the following path(s):
   1) {  h^#(x, c(y, z)) -> c_0(h^#(c(s(y), x), z))
       , h^#(c(s(x), c(s(0()), y)), z) -> c_1(h^#(y, c(s(0()), c(x, z))))}
      
      The usable rules for this path are empty.
      
        We have oriented the usable rules with the following strongly linear interpretation:
          Interpretation Functions:
           h(x1, x2) = [0] x1 + [0] x2 + [0]
           c(x1, x2) = [0] x1 + [0] x2 + [0]
           s(x1) = [0] x1 + [0]
           0() = [0]
           h^#(x1, x2) = [0] x1 + [0] x2 + [0]
           c_0(x1) = [0] x1 + [0]
           c_1(x1) = [0] x1 + [0]
        
        We have applied the subprocessor on the resulting DP-problem:
        
          'Weight Gap Principle'
          ----------------------
          Answer:           YES(?,O(n^2))
          Input Problem:    innermost DP runtime-complexity with respect to
            Strict Rules:
              {  h^#(x, c(y, z)) -> c_0(h^#(c(s(y), x), z))
               , h^#(c(s(x), c(s(0()), y)), z) -> c_1(h^#(y, c(s(0()), c(x, z))))}
            Weak Rules: {}
          
          Details:         
            We apply the weight gap principle, strictly orienting the rules
            {h^#(c(s(x), c(s(0()), y)), z) -> c_1(h^#(y, c(s(0()), c(x, z))))}
            and weakly orienting the rules
            {}
            using the following strongly linear interpretation:
              Processor 'Matrix Interpretation' oriented the following rules strictly:
              
              {h^#(c(s(x), c(s(0()), y)), z) -> c_1(h^#(y, c(s(0()), c(x, z))))}
              
              Details:
                 Interpretation Functions:
                  h(x1, x2) = [0] x1 + [0] x2 + [0]
                  c(x1, x2) = [1] x1 + [1] x2 + [0]
                  s(x1) = [1] x1 + [8]
                  0() = [0]
                  h^#(x1, x2) = [1] x1 + [1] x2 + [1]
                  c_0(x1) = [1] x1 + [0]
                  c_1(x1) = [1] x1 + [0]
              
            Finally we apply the subprocessor
            'fastest of 'combine', 'Bounds with default enrichment', 'Bounds with default enrichment''
            ------------------------------------------------------------------------------------------
            Answer:           YES(?,O(n^2))
            Input Problem:    innermost DP runtime-complexity with respect to
              Strict Rules: {h^#(x, c(y, z)) -> c_0(h^#(c(s(y), x), z))}
              Weak Rules:
                {h^#(c(s(x), c(s(0()), y)), z) -> c_1(h^#(y, c(s(0()), c(x, z))))}
            
            Details:         
              The problem was solved by processor 'combine':
              'combine'
              ---------
              Answer:           YES(?,O(n^2))
              Input Problem:    innermost DP runtime-complexity with respect to
                Strict Rules: {h^#(x, c(y, z)) -> c_0(h^#(c(s(y), x), z))}
                Weak Rules:
                  {h^#(c(s(x), c(s(0()), y)), z) -> c_1(h^#(y, c(s(0()), c(x, z))))}
              
              Details:         
                'sequentially if-then-else, sequentially'
                -----------------------------------------
                Answer:           YES(?,O(n^2))
                Input Problem:    innermost DP runtime-complexity with respect to
                  Strict Rules: {h^#(x, c(y, z)) -> c_0(h^#(c(s(y), x), z))}
                  Weak Rules:
                    {h^#(c(s(x), c(s(0()), y)), z) -> c_1(h^#(y, c(s(0()), c(x, z))))}
                
                Details:         
                  'if Check whether the TRS is strict trs contains single rule then fastest else fastest'
                  ---------------------------------------------------------------------------------------
                  Answer:           YES(?,O(n^2))
                  Input Problem:    innermost DP runtime-complexity with respect to
                    Strict Rules: {h^#(x, c(y, z)) -> c_0(h^#(c(s(y), x), z))}
                    Weak Rules:
                      {h^#(c(s(x), c(s(0()), y)), z) -> c_1(h^#(y, c(s(0()), c(x, z))))}
                  
                  Details:         
                    a) We first check the conditional [Success]:
                       We are considering a strict trs contains single rule TRS.
                    
                    b) We continue with the then-branch:
                       The problem was solved by processor 'fastest of 'Matrix Interpretation', 'Matrix Interpretation', 'Matrix Interpretation'':
                       'fastest of 'Matrix Interpretation', 'Matrix Interpretation', 'Matrix Interpretation''
                       --------------------------------------------------------------------------------------
                       Answer:           YES(?,O(n^2))
                       Input Problem:    innermost DP runtime-complexity with respect to
                         Strict Rules: {h^#(x, c(y, z)) -> c_0(h^#(c(s(y), x), z))}
                         Weak Rules:
                           {h^#(c(s(x), c(s(0()), y)), z) -> c_1(h^#(y, c(s(0()), c(x, z))))}
                       
                       Details:         
                         The problem was solved by processor 'Matrix Interpretation':
                         'Matrix Interpretation'
                         -----------------------
                         Answer:           YES(?,O(n^2))
                         Input Problem:    innermost DP runtime-complexity with respect to
                           Strict Rules: {h^#(x, c(y, z)) -> c_0(h^#(c(s(y), x), z))}
                           Weak Rules:
                             {h^#(c(s(x), c(s(0()), y)), z) -> c_1(h^#(y, c(s(0()), c(x, z))))}
                         
                         Details:         
                           Interpretation Functions:
                            h(x1, x2) = [0 0 0] x1 + [0 0 0] x2 + [0]
                                        [0 0 0]      [0 0 0]      [0]
                                        [0 0 0]      [0 0 0]      [0]
                            c(x1, x2) = [1 0 0] x1 + [1 0 0] x2 + [0]
                                        [0 1 1]      [0 1 0]      [1]
                                        [0 0 0]      [0 0 0]      [0]
                            s(x1) = [0 1 1] x1 + [0]
                                    [0 0 0]      [0]
                                    [0 0 0]      [0]
                            0() = [0]
                                  [1]
                                  [1]
                            h^#(x1, x2) = [1 0 0] x1 + [0 1 0] x2 + [0]
                                          [0 0 0]      [0 0 0]      [0]
                                          [0 0 0]      [0 0 0]      [0]
                            c_0(x1) = [1 0 0] x1 + [0]
                                      [0 0 0]      [0]
                                      [0 0 0]      [0]
                            c_1(x1) = [1 0 0] x1 + [0]
                                      [0 0 0]      [0]
                                      [0 0 0]      [0]